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thu ti


Báo cho bạn khi có người bình luận tiếp theo đề tài này bằng điện thư
$latex dfrac{x+1}{x+2}$

$frac{1}{{x^2 + 1}}$

left ( begin{array} {ccc} 2 & -1 & 1  -1 & 2  & -1  0 & 0 & 1 end{array} right ).
left ( begin{array} {ccc} 2 & -1 & 1  -1 & 2 & -1  0 & 0 & 1 end{array} right )

Categories: Story
  1. May 13, 2010 at 5:37 pm

    \left \{ \begin{array}{l} x^2 + y^3 =1 \\ x^4 + y^4 = 1 \\ \end{array} \right.

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